`1/sqrt2xxsqrt2=`

Solve for x. x=(sqrt(384))/(sqrt2xxsqrt3)

The matrix A=[{:(1/sqrt2,1/sqrt2),((-1)/sqrt2,(-1)/sqrt2):}] is

sin( 67 1/2)^(@) + cos( 67 1/2)^(@) is equal to A) 1/2sqrt(4+2sqrt(2)) , B) 1/2sqrt(4-2sqrt(2)) , C) 1/4(sqrt(4+2sqrt(2))) , D) 1/4(sqrt(4-2sqrt(2)))

1/(sqrt3 + sqrt2) + 1/(sqrt3 -sqrt2)=

Solve for x. x=sqrt(20)xxsqrt5

Solve for x. x=sqrt2xxsqrt6xxsqrt(12)

{:("Quantity A","Quantity B"),((sqrt6xxsqrt(18))/(sqrt9),(sqrt8xxsqrt(12))/(sqrt6)):}

Simplify the following : (i) sqrt(-25)xxsqrt(-36) (ii) sqrt(-25)xxsqrt(49)

Write the value of sqrt(-25)xxsqrt(-9)dot

The value of 6+ log_(3//2) (1/(3sqrt2)sqrt(4-1/(3sqrt2)sqrt(4-1/(3sqrt2)sqrt(4-1/(3sqrt2)...)))) is ________.