In the reaction,
`P(g)+2Q(g)rarr4R(g)+3S(l)`
When `1` mole of `P` and `1` mole of `Q` are allowed to react to the completion of reaction, then
All `P` will be consumed
`4` mole of `R` will form
`2` mole of `S` will form
All `Q` will consumed

In the reaction, 4NH_(3)(g)+5O_(2)(g) rarr 4NO(g)+6H_(2)O(g) , when 1 mole of ammonia and 1 mole of O_(2) are made to react to completion

In the reaction A + B hArr C + D, 4 moles of A react with 4 moles of B and form 2 moles each of C and D. The value of Ke for the reaction is

For the reaction A(g) +3B(g) hArr 2C(g) at 27^(@)C , 2 moles of A , 4 moles of B and 6 moles of C are present in 2 litre vessel. If K_(c) for the reaction is 1.2, the reaction will proceed in :

For the reaction A_((g)) + 3B_((g)) hArr 2C_((g)) at 27^(@)C .2 mole of A, 4 moles of B and 6 moles of C are present in 2 lit vessel. If K_(c) for the reaction is 1.2, the reaction will proceed in

For the reaction A(g) +3B(g) hArr 2C(g) at 27^(@)C , 2 moles of A , 4 moles of B and 6 moles of C are present in 2 litre vessel. If K_(c) for the reaction is 1.2, the reaction will proceed in :

In the reaction X(g)+Y(g)hArr2Z(g),2 mole of X,1 mole of Y and 1 mole of Z are placed in a 10 litre vessel and allowed to reach equilibrium .If final concentration of Z is 0.2 M , then K_(c) for the given reaction is :

A mixture of 1.0 mole of Al and 3.0 mole of Cl_(2) are allowed to react as: 2Al(s)+3Cl_(2)(g) to 2AlCl_(3)(g) . Then moles of excess reagent left unreacted is:

In a system P_(s) hArr 2Q_(g) + R_(g) , at equilibrium is concentration of 'Q' is doubled than how many times the concentration of R at equilibrium will be :-

9 moles of "D" and 14 moles of E are allowed to react in a closed vessel according to given reactions. Calculate number of moles of B formed in the end of reaction, if 4 moles of G are present in reaction vessel. (percentage yield of reaction is mentioned in the reaction) Step -1 3D+4E 80%rarr5C+A Step-2 3C+5G 50%rarr 6B+F