`1.25g` of organic compound is heated with fuming nitric acid in presence of `AgNO_(3)` in Carius tube and `752mg` of `AgBr` is formed. What is the weight (in mg ) of bromine present in `0.25g` of same organic compound? (Ag- 108&Br-80)

In Carius method, halogen containing organic compound is heated with funning nitric acid in the presence of:

0.99 g of an organic compound containing halogen when heated with fuming nitric acid in the presence of silver nitrate in a carius tube gave 0.287 g of white precipitate. The percentage of halogen in the compound is about

1.09g of an organic compound on heating with fuming nitric acid followed by addition of AgNO_(3) ,give 0.1422g AgCl .The percentage of chlorine in the compound is

1.09g of an organic compound on heating with fuming nitric acid followed by addition of AgNO_(3) ,give 0.1422g AgCl .The percentage of chlorine in the compound is

0.25g of an organic compound on heating with conc. HNO_(3) and silver nitrate in carius tube gave 0.20g of AgBr , then the percentage of bromine in the compound is (Atomic Mass of Ag=108u,Br=80u )

0.25g of an organic compound on heating with conc. HNO_(3) and silver nitrate in carius tube gave 0.20g of AgBr , then the percentage of bromine in the compound is (Atomic Mass of Ag=108u,Br=80u )

0.156 gm of an organic compound on heating with fuming HNO_3 and AgNO_3 gives 0.235 gm of Agl . Calculate the percentage of iodine in the compound.

From 0.2g of compound, 0.188g of AgBr is formed by Carius method. Find % of Br?

An organic compound contains 46.78% of a halogen AgX. When 2.00 g of this compound is heated with fuming HNO_3 in the presence of AgNO_3 , 2.21 g of X was formed. The halogen X is [Given: atomic weight of Ag = 108, F = 19, C1=35.5, Bi = 80, l = 127]