A force `F=-k(xhat i+yhat j)` (where "k" is a positive constant] acts on a particle moving is the x-y plane.Starting from origin,the particle is taken to (a,a) and then to `((a)/(sqrt(2)),0)`. The total work done by the force F on the particle is :-

A force F=-k(^hati + x^hatj) (where k is a positive constant) acts on a particle moving in the x-y plane. Starting from the origin, the particle is taken along the positive x-axis to the point (a,0) and then parallel to the y-axis to the point (a,a) . The total work done by the force F on the particle is (a) -2ka^(2) , (b) 2ka^(2) , (c) -ka^(2) , (d) ka^(2)

A force F=-K(yhati+xhatj) (where K is a positive constant) acts on a particle moving in the x-y plane. Starting from the origin, the particle is taken along the positive x-axis to the point (a, 0) , and then parallel to the y-axis to the point (a, a) . The total work done by the force F on the particle is

A force vecF=(4hati+5hatj)N acts on a particle moving in XY plane. Starting from origin, the particle first goes along x-axis to the point (5.0) m and then parallel to the Y-axis to the point (5,4 m. The total work done by the force on the particle is

Forces acting on a particle moving in a straight line varies with the velocity of the particle as F = (alpha)/(upsilon) where alpha is constant. The work done by this force in time interval Delta t is :

A force F acting on a particle varies with the position x as shown in figure. Find the work done by this force in displacing the particle from

A uniform force of (3 hat(i)+hat(j)) newton acts on a particle of mass 2 kg . Hence the particle is displaced from position (2 hat(i)+hat(k)) meter to position (4 hat(i)+ 3hat(j)-hat(k)) meter. The work done by the force on the particle is :

A particle of mass m initially at rest. A variabl force acts on the particle f=kx^(2) where k is a constant and x is the displacment. Find the work done by the force f when the speed of particles is v.

A particle is moving along the x-axis and force acting on it is given by F=F_0sinomegaxN , where omega is a constant. The work done by the force from x=0 to x=2 will be

The potential energy function of a particle in the x-y plane is given by U =k(x+y) , where (k) is a constant. The work done by the conservative force in moving a particlae from (1,1) to (2,3) is .

Force acting on a particle varies with displacement as shown is Fig. Find the work done by this force on the particle from x=-4 m to x = + 4m. .