Magnetic field at point "P"'due to given current distribution is :-

(1) `(mu_(0))/(4 pir)``(1+sqrt(2))``odot`

(2) `(mu_(0)I)/(2 pir)``(1+sqrt(2))``odot`

(3) `(mu_(0)I)/(4 pir)``(1+sqrt(2))``otimes`

(4) `(mu_(0)I)/(2 pi r)``(1+sqrt(2))``otimes`

The magnetic field at the origin due to a current element I vec(dl) placed at position r is (i) ((mu_(0)i)/(4pi))((dvec(l)xxvec(r))/(r^(3))) -((mu_(0)i)/(4pi))((dvec(l)xxvec(r))/(r^(3))) (iii) ((mu_(0)i)/(4pi))((vec(r)xxdvec(l))/(r^(3))) -((mu_(0)i)/(4pi))((vec(r)xxdvec(l))/(r^(3)))

The dimensions of (mu_(0)epsilon_(0))^(-1//2) are

lim_( r to 0) pir^(2)

The speed of electromagnetic waves in vacuum is - (A) sqrt(in_0mu_0) (B) 1/ sqrt(mu_0in_0) (C) in_0mu_0 (D) 1/ (in_0mu_0)

Find the magnetic field at point P due to a straight line segment AB of length 6 cm carrying a current of 5A . (See figure) (mu_(0) = 4 pi xx 10^(-7) N-A^(-2)) . .

If 0ltxltpi and cosx + sinx =1/2 , then tanx is (1) (4-sqrt(7))/3 (2) -(4+sqrt(7))/3 ( 3) (1+sqrt(7))/4 (4) (1-sqrt(7))/4

sin^(-1)sqrt((2-sqrt(3))/4)+cos^(-1)(sqrt(12)/4)+sec^(-1)(sqrt(2))= (a) 0 (b) pi/4 (c) pi/6 (d) pi/2

Evaluate : (i) int_(0)^(1)(3sqrt(x^(2))-4sqrt(x))/(sqrt(x))dx , (ii) int_(0)^(1)x cos(tan^(1)x)dx

The dimensions of (1)/(sqrt(mu_(0)epsi_(0))) are the same as that of

Check which of the following are solutions of the equations x-2y=4 and which are not: (i) (0,2) (ii) (2,0) (iii) (4,0) (iv) (sqrt(2),4sqrt(2)) (v) (1,\ 1)