The point at which the normal to the cur...

The point at which the normal to the curve `y=x+(1)/(x)` , x > 0 is perpendicular to the line 3x - 4y - 7 = 0 is:
a) (2,5/2)
b) (+2,5/2)
c) (-1/2,5/2)
d) (1/2,5/2)

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