`int e^x x^3 logx dx`

(i) int e^(3logx)dx

The integral inte^x(f(x)+f\'(x))dx can be solved by using integration by parts such that: I=inte^xf(x)dx+inte^xf\'(x)dx=e^xf(x)-inte^xf\'(x)dx+inte^xf\'(x)dx=e^xf(x)+C , and inte^(ax)(f(x)+(f\'(x))/a)dx=e^(ax)f(x)/a+C ,Now answer the question: inte^x x^x(2+logx)= (A) e^x x^xlogx+C (B) e^x+x^x+C (C) e^x x(logx)^2+C (D) e^x.x^x+C

inte^(2x^(2)+logx)dx=

int e^x/(e^x+3)dx

Show that : e^( int ( dx /( xlogx ) )) = e^( log(logx )) = log x

Evaluate int e^x(1/logx-1/(x(logx)^2)) dx

Evaluate : int_1^3 cos( logx )/x dx

(i) int x^2 e^x dx (ii) int x^2 e^(3x) dx (ii) int x^3 e^x dx

int_a^b logx/x^2dx

I= int (logx)^2/x dx