Solve `sin theta/(1-cos theta)`.

Solve ((1-sin theta)/(cos theta))

Solve sin2 theta+cos theta=0

Solve sin^(2) theta-cos theta=1/4, 0 le theta le 2pi .

Solve sin^2 theta- cos theta =1/4 " for " theta and write the value of theta in the interval 0 le theta le 2 pi

Solve sin 2 theta+cos theta=0 .

Solve (3 sin theta-sin 3 theta)/(sin theta)+(cos 3 theta)/(cos theta)=1 .

1- (sin ^ (2) theta) / (1 + cos theta) + (1 + cos theta) / (sin theta) - (sin theta) / (1-cos theta) - (1) / (sec theta)

1-(sin^(2)theta)/(1+cos theta)+(1+cos theta)/(sin theta)-(sin theta)/(1-cos theta) equals

Solve sin theta+cos theta=sqrt(2) cos A .