In a gravity free space a lift shown moves upwards with acceleration `a=2tm/s^(2)` starting at `t=0` Strings and pulley are light and m=1kg.If any of the strings can take maximum tension of 40N,then find time at which one of the two strings break.(Strings are long enough)

A stone of mass 0.5 kg is attached to a string of length 2 m and is whirled in a horizontal circle. If the string can with stand a tension of 9N, the maximum velocity with which the stone can be whirled is:

A lift of mass 200 kg is moving upward with an acceleration of 3m//s^(2) . If g=10 m//s^(2) then the tension of string of the lift will be :

A lift starts from rest with a constant upward acceleration It moves 1.5 m in the first 0.4 A person standing in the lift holds a packet of 2 kg by a string Calculate the tension in the string during the motion .

A lift of mass 1000kg is moving with an acceleration of 1m//s^(2) in upward direction. Tension developed in the string, which is connected to the lift, is.

A lift of mass 1000kg is moving with an acceleration of 1m//s^(2) in upward direction. Tension developed in the string, which is connected to the lift, is.

A lift of mass 100 kg is moving upwards with an acceleration of 1 m//s^(2) . The tension developed in the string, which is connected to lift is ( g=9.8m//s^(2) )

A particle of mass 100 g tied to a string is rotated along the circle of radius 0.5 m. The breaking tension of the string is 10 N. The maximum speed with which particle can be rotated without breaking the string is

A body of mass 0.5 kg is whirled with a velocity of 2 ms^(-1) using 0.5 m length string which can be withstand a tension of 15 N, Neglecting the force of gravity on the body predict whether or not the string will break.

One end of a string of length L is tied to the ceiling of a lift accelerating upwards with an acceleration 2g. The other end o the string is free. The linear mass density of the string varies linearly from 0 to lamda from bottom to top. The acceleration of a wave pulled through out the string is (pg)/(4) . Find p.

An object is resting at the bottom of two strings which are inclined at an angle of 120^(@) with each other. Each string can withstand a tension of 20 N. The maximum weight of the object that can be sustained without breaking the string is