A body is thrown vertically up with some velocity (at t=0) crosses a fixed point P in its path at t=4s and again at t=6s.The velocity of projection of the body will be

A body is projected vertically up with u. Its velocity at half its maximum height is

A body is projected up with velocity u. It reaches a point in its path at times t_1 and t_2 seconds from the time of projection. Then (t_1+t_2) is

A body is thrown horizontally from the top of a tower. It reaches the ground after 4s at an angle 45° to the ground. The velocity of projection is

A body is thrown vertically up with certain velocity. If h is the maximum height reached by it, its position when its velocity reduces to 1/3 of its velocity of projection is at

A body is thrown vertically up with a velocity of 100 m/s and another one is thrown 4 sec after the first one. How long after the first one is thrown will they meet?

A body is thrown vertically upwards which graph represents variation of velocity w.r.t time

A body is thrown vertically up with certain initial velocity, the potential and kinetic energies of the body are equal is thrown with double the velocity upwards, the ratio of potential and kinetic energies upwards, the ratio of potential and kinetic energies of the body when it crosses the same point, is

A body thrown vertically up with velocity u reaches the maximum height h after T seconds. Which of the following statements is true ?

A body is projected vertically up with velocity 98 "ms"^(-1) . After 2 s if the acceleration due to gravity of earth disappears, the velocity of the body at the end of next 3 s is

From the top of a tower body A is thrown up vertically with velocity u and another body B is thrown vertically down with the same velocity u.If V_(A) and V_(B) are their velocities when they reach the ground and t_(A) and t_(B) are their times of flight ,then