A particle moves along a straight line such that its velocity `(v)` at any time `(t)` is given by `v=(2t-1)m s^(-1)`, where `t` is in seconds. Total distance traveled by the particle in first second is

A particle moves along a straight line such that its position x at any time t is x=3t^(2)-t^(3) , where x is in metre and t in second the

A particle moves along a straight line such that its displacement s at any time t is given by s=t^3-6t^2+3t+4m , t being is seconds. Find the velocity of the particle when the acceleration is zero.

The velocity 'v' of a particle moving along straight line is given in terms of time t as v=3(t^(2)-t) where t is in seconds and v is in m//s . The distance travelled by particle from t=0 to t=2 seconds is :

A particle moves along a straight line its velocity dipends on time as v=4t-t^(2) . Then for first 5 s :

A particle in moving in a straight line such that its velocity is given by v=12t-3t^(2) , where v is in m//s and t is in seconds. If at =0, the particle is at the origin, find the velocity at t=3 s .

A particle is moving in a striaght line and at a given time, its displacement is S = t^(3) - 6t^(2) + 9t , where t is in seconds and S is in meter . The total distance travelled by the particle during the first five seconds is

A particle moves along a straight line such that its displacement at any time t is given by s = 3t^(3)+7t^(2)+14t + 5 . The acceleration of the particle at t = 1s is

A particle starts from rest at t=0 and moves along a straight line with a variable acceleration given by a (t)=(3t+1)ms^(-2) ,where t],[ is in seconds.The velocity of the particle at t=4s is