If `cosectheta=2` then `tantheta` is equal to
`(A) sqrt3/2`
`(B) 1/sqrt3`
`(C) 1/2`
`(D) 2/sqrt3`

Delta ABC has a right angle at A. If BC = sqrt2 and AB = AC = 1 then sin B is equal to (a) (1)/(sqrt2) (b) sqrt2 (c) (sqrt3)/(2) (d) sqrt3

sintheta=-1/2 and tantheta=-1/sqrt(3)

If sintheta=-1/2 and tantheta=1/sqrt(3) then theta is equal to,

Let alpha = tan^-1 (1/2)+tan^-1(1/3) , beta=cos^-1(2/3)+cos^-1(sqrt5/3) , gamma=sin^-1(sin((2pi)/3))+1/2cos^-1(cos((2pi)/3)) cosalpha+cosbeta+cosgamma is equal to (A) (sqrt(2)-1)/2 (B) (sqrt(2)+1)/2 (C) (sqrt(2)+sqrt(3))/2 (D) ((sqrt(3)-sqrt(2))/2

If A(1,-1,2),B(2,1,-1)C(3,-1,2) are the vertices of a triangle then the area of triangle ABC is (A) sqrt(12) (B) sqrt(3) (C) sqrt(5) (D) sqrt(13)

If tan^(-1)x+2cot^(-1)x=(2 pi)/(3), then x, is equal to (a) (sqrt(3)-1)/(sqrt(3)+1) (b) 3 (c) sqrt(3)(d)sqrt(2)

sintheta=sqrt(3)/2 and tantheta=-sqrt(3)

If cos^-1( (x^2-1)/(x^2+1))+ tan^-1( (2x)/(x^2-1)) = (2pi)/3 , then x equal to (A) sqrt(3) (B) 2+sqrt(3) (C) 2-sqrt(3) (D) -sqrt(3)

If cosectheta=b//a , then (sqrt3cottheta+1)/(tantheta+sqrt(3)) is equal to: