`int_0^(pi/2)sin^6 x cos^4 x dx`

int_0^(pi/2) sin^6x dx

int_(0)^(pi//2) x sin x cos x dx

int_(0)^( pi/2)sin^(2)x cos x dx

int_(0)^(pi)sin 5 x cos 4x dx=

Evaluate (i) int_0^(pi//4) sin x cos x dx (ii) int_0^(pi//2) (1 + cos x)^(1//2) dx (iii) int_0^(pi//2) (1 + sin x)^(1//2) dx (iv) int_0^(pi//4) (1 -cos 2x)^(1//2)dx

int_(0)^( pi/4)(sin x-cos x)dx

int_0^pi sin^4x cos^4x dx

If int_(0)^(pi//2)sin^(4)x cos^(2)x dx=(pi)/(32) , then int_(0)^(pi//2)sin^(2)x cos^(4)x dx=

int_(0)^(pi/2)(sin^(2)x*cos x)dx=