If `Cosθ + Cos^2 θ = 1` then find the value of `Sin^2θ + Sin^4θ` =?

If θ lies in the first quadrant and cos^(2) θ – sin^(2) θ = 1/2 , then the value of tan^(2)2θ + sin^(2)3θ is: यदि θ प्रथम चतुथथांश में है और cos^(2) θ – sin^(2) θ = 1/2 , तो tan^(2)2θ + sin^(2)3θ का मान है:

If cot θ = 21/20 then what then value of sec θ ?

"If 2 | α | + 3 | β | = 6 ,then find the minimum value of α 2 + β 2 − 12 α cos θ − 12 β sin θ + 36 ,where θ ∈ R

If {(2 sin θ – cos θ) / (cos θ + sin θ)} = 1, then the value of cot θ is (A) 1/2 (B) 1/3 (C ) 3 (D) 2

If 2cos^(2)θ + 3sinθ = 3 , where 0^circ lt θ lt 90^circ , then what is the value of sin^(2)2θ + cos^2 (θ) + tan^(2)2θ + cos^(2) 2θ = ? यदि 2cos^(2)θ + 3sinθ = 3 , जहा 0^circ lt θ lt 90^circ तो sin^(2)2θ + cos^(2(θ + tan^(2)2θ + cos^(2)2θ का मान बराबर है :

If θ is an acute angle and sinθ=cosθ, find the value of 2tan^2θ+sin^2θ−1.

If cotθ = sqrt6 , then the value of is: (cosec^(2)θ + sec^(2)θ)/(cosec^(2)θ − sec^(2)θ) यदि cotθ = sqrt6 है तो (cosec^(2)θ + sec^(2)θ)/(cosec^(2)θ − sec^(2)θ) का मान हैः

If cosecθ=secθ, then value of θ is

If 5sin θ – 4cos θ = 0, 0^circ lt θ lt 90^circ , then the value of (5sinθ− 2cosθ)/ (5 sin θ + 3cosθ) is: यदि 5sin θ – 4cos θ = 0, 0^circ lt θ lt 90^circ है, तो (5sinθ− 2cosθ)/ (5 sin θ + 3cosθ) का मान है:

If 3 − 2sin^2θ − 3cosθ = 0, 0^circ le θ le 90^circ , then what is the value of (2cosecθ + tanθ) ? यदि 3 − 2sin^2θ − 3cosθ = 0, 0^circ le θ le 90^circ है तो (2cosecθ + tanθ) का मान क्‍या है?