solve : `int_(0)^(b)cos xdx`

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Evaluate: int_(a)^(b)cos xdx

int_(0)^((pi)/(2))cos xdx=

int_(0)^( pi)cos^(5)xdx

int_(0)^((pi)/(2))cos xdx=?

int_(0)^(2 pi)cos^(4)xdx

int_(0)^(2 pi)cos^(7)xdx

int_(0)^( pi)cos^(3)xdx=

int_(0)^((pi)/(6))cos3xdx

int_(0)^( pi/2)cos^(6)xdx