A particle moves along `x` axis given by `X=A sin((pi t)/(6))`.The ratio of distance travelled by it in `1^(st) ` second and `2^(nd)` second is

A particle moves along the X-axis as x=u(t-2 s)+a(t-2 s)^2 .

A particle moves along the X-axis as x=u(t-2s)=at(t-2)^2 .

Velocity of a particle moving along a straight line at any time 't' is give by V = cos((pi)/(3)t) . Then the distance travelled by the particle in the first two seconds is :

The position of a particle along x-axis at time t is given by x=1 + t-t^2 . The distance travelled by the particle in first 2 seconds is

Position of a particle moving along x-axis is given by x=2+8t-4t^(2) . The distance travelled by the particle from t=0 to t=2 is:-

A body is freely dropped from a height h above the ground. Find the ratio of distances fallen in first one second, first two seconds, first three second first two seconds, first three seconds, also find the rato of distances fallen in 1^(st) second, in 2^(nd) second, in 3^(rd)

A particle moves on x-axis as per equation x = (t^(3)- 9t^(2) +15+2)m . Distance travelled by the particle between t = 0 and t = 5s is

Time period of a particle executing SHM is 8 sec. At t=0 it is at the mean position. The ratio of the distance covered by the particle in the 1st second to the 2nd second is:

Velocity time graph for a particle moving in a line is given. Calculate the displacement of the particle and distance travelled in first 4 seconds.

A particle is moving on X- axis. Its velocity time graph is given in the figure. Find distance travelled by the particle in 5 sec .