The dimensions of electric potential are
(A) `[ML^(2)T^(-3)A^(-1)]`
(B) `[ML^(2)T^(-1)A^(-1)]`
(C) `[ML^(2)T^(-1)A^(-2)]`
(D) `[ML^(2)T^(-3)A^(-2)]`

Dimension of sqrt((in_(0))/(mu_(0))) are (A) [M L^(2) T^(-3) A^(-2)] (B) [M^(-1) L^(-2) T^(3) A^(2)] (C) [M^(2)L^(2)T^(-3) A^(2)] (D) [M^(-1) L^(2) T^(3) A^(2)]

The dimensions ML^-1T^-2 may correspond to

Name of units of some physical quantities are given in List - 1 and their dimensional formulae are given in List - 2 , Match correct pair in lists. {:("List - 1","List - 2"),((a) pascal ,(e) L^2T^(-2)K^(-1)),((b) NmK^(-1), (f) MLT^(-3)K^(-1)),((c) J Kg^(-1)K^(-1), (g) ML^(-1)T^(-2)),((d) Wm^(-1)K^(-1), (h) ML^(2)T^(-2)K^(-1)):}

The dimension ML^-1T^-2 can correspond to

Match the following {:(,,"Table-1",,"Table-2"),(,(A),L,(P),[M^(0)L^(0)T^(-2)]),(,(B),"Magnetic Flux",(Q),[ML^(2)T^(-2)A^(-1)]),(,(C),LC,(R),[ML^(2)T^(-2)A^(-2)]),(,(D),CR^(2),(S),"None"):}

The dimensional formula [ML^(-1)T^(-2)] is for the quantity

Assertion : Pressure has the dimensions of energy density. Reason : Energy density = ("energy")/("volume")=(["ML"^(2)"T"^(-2)])/(["L"^(3)]) =["ML"^(-1)"T"^(-2)]="pressure"

{:(,"Column I",,"Column II"),(("A"),"Electrical resistance",(p),["M"^(-1)"L"^(-2)"T"^(4)"A"^(2)]),(("B"),"Capacitance",(q),["ML"^(2)"T"^(-2)"A"^(-2)]),(("C"),"Magnetic field",(r),["ML"^(2)"T"^(-3)"A"^(-2)]),(("D"),"Inductance",(s),["MT"^(-2)"A"^(-1)]):}

The dimensional formula ML^(2)T^(-2) stands for

The dimensional formula ML^2T^(-2) represents