Fill `10a^2-12b^2=2(.........-6b^2)`

Simplify the following expression: 5a^(2)b^(2)-4a^(2)b-(-10a^(2)b^(2))

If 2a=b, the pair of equations ax+by=2a^(2)-3b^(2),x+2y=2a-6b possess

Factorise each of the following: (i) 8a^3+b^3+12 a^2b+6a b^2 (ii) 8a^3-b^3-12 a^2b+6a b^2 (iii) 27-125 b^3-135 a+225 a^2 (iv) 64 a^3-27 a^3-144 a^2b+108 a b^2 (v) 27 p^3-1/(216)-9/2p^2+1/4p

Factorize: 8a^(3)-b^(3)-12a^(2)b+6ab^(2)

Factorize: 8a^(3)+b^(3)+12a^(2)b+6ab^(2)

find the sum of 2a(a^(2)+b^(2)),2b^(2)(b-a) and 12b(a^(2)-b^(2))

Subtract the sum of 12ab-10b^2 -18a^2 and 9ab + 12 b^2+ 14a^2 " from the sum of " ab + 2b^2 and 3b^2-a^2 .

If 6a^(2)+12b^(2)+2c^(2)+17ab-10bc-7ac=0 then all the lines represented by ax+by+c=0 are concurrent at the point