Solve: `sintheta/costheta=costheta/sintheta`

What is sintheta/(1+costheta)+(1+costheta)/sintheta equal to ?

Prove that : (1+sintheta)/(costheta)+(costheta)/(1+sintheta)=2sectheta

Show that costheta.[{:(costheta,sintheta),(-sintheta,costheta):}]+sintheta.[{:(sintheta,-costheta),(costheta,sintheta):}]=I.

costheta[{:(costheta,-sin theta),(sintheta,costheta):}]+sintheta[{:(sintheta,costheta),(-costheta,sintheta):}]=?

prove that- (sintheta+1-costheta)/(costheta-1+sintheta)=(1+sintheta)/costheta

Simplify: cos theta[{:(costheta,sintheta),(-sintheta,costheta):}]+sintheta[{:(sin theta ,-costheta),(costheta, sintheta):}]

Consider a matrix A (theta)= [(sintheta,costheta),(-costheta,sintheta)] then

Evaluate Delta=|{:(sintheta, costheta),(-costheta,sintheta):}|

If (sintheta+costheta)/(sintheta-costheta)=3 and theta is an acute angle, then the value of (3sintheta+4costheta)/(8costheta-3sintheta) is

Prove that : (sintheta)/(1+costheta)+(1+costheta)/(sintheta)=2"cosec"theta