Number of electrons present in `3.8g` of `F^(-)` ion is (Atomic weight of `F=19)`
A)`1.8N_(A)`
B) `2N_(A)`
C) `2.3N_(A)`
D) `1.5N_(A)`

In Bohr's model, r_(n,z)= radius of n^(th) orbit with atomic number Z u_(n,z) =P.E of electron in n^(th) orbit with atomic number Z K_(n,z) = K.E of electron in n^(th) orbit with atomic number Z V_(n,z) = velocity of electron in n^(th) orbit with atomic number Z T_(n,z)= time period of revolution in n^(th) orbit with atomic number Z {:(Column I,Column II),((A)U_(1.2),K_(1.1),(p)1:8),((B)r_(2.1),r_(1.2),(q)-8:1),((C)V_(1.3),V_(3.1),(r)9:1),((D)T_(1.2),T_(2.2),(s)8:1):}

The number of diagonal matrix,A or order n which A^(3)=A is a . is a a.1 b.0 c.2^(n) d.3^(n)

For all n inN,3*5^(2n+1)+2^(3n+1) is divisible by (A) 19 (B) 17 (C) 23 (D) 25

f (n) = cot ^ (2) ((pi) / (n)) + cot ^ (2) backslash (2 pi) / (n) + ............ + cot ^ (2) backslash ((n-1) pi) / (n), (n> 1, n in N) then lim_ (n rarr oo) (f (n)) / (n ^ (2)) is equal to (A) (1) / (2) (B) (1) / (3) (C) (2) / (3) (D) 1, (n> 1, n in N)

Electronic transition in He^(+) ion takes from n_(2) " to " n_(1) shell such that : 2n_(2)+3n_(1)=18 2n_(2)+3n_(1)=6 What will be the total number of photons emitted when electrons transit to n_(1) shell?

Assign the position of the element having outer electronic configuration a. ns^(2)np^(4) for n=3 b. (n-1)d^(2)ns^2 for n=4 and c. (n-2)_(f)^(7)(n-1)d^(1)ns^(2) for n=6 , in the periodic table.

If n is a whole number greater than 1, then n^(2)(n^(2)-1) is always divisible by 8 (b) 10 (c) 12 (d) 16

" The maximum number of electrons in "K" atom "(Z=19)" with quantum numbers "n=3,m=+1,s=+(1)/(2)" is "