|x - 5 | = 2
`therefore` x - 5 = `square`
x = `2 + square`
x = `square`

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The perimeter of a square is 60x m. Find the side of the square.

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a square is inscribed in the circle x^2 + y^2- 10x - 6y + 30 = 0. One side of the square is parallel to y = x + 3, then one vertex of the square is :

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Find the square of : (i) 3x + (2)/(y)