x + 4 =9
`therefore` x + 4 - `square` = 9 - `square`
`therefore` x = `square`

The sides of a square are x =4, x = 7, y =1 and y = 4 . The equation of the circumcircle of the square is :

Find the square of : (x) x + (1)/(x) - 1

The perimeter of a square is 60x m. Find the side of the square.

Let one of the vertices of the square circumseribing the circle x^(2) + y^(2) - 6x -4y + 11 = 0 be (4, 2 + sqrt(3)) The other vertices of the square may be

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a square is inscribed in the circle x^2 + y^2- 10x - 6y + 30 = 0. One side of the square is parallel to y = x + 3, then one vertex of the square is :

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A square is inscribed in a circle with area 9z. What is the area of the square?