The equivalent resistance between `A` and `B` of the network shown in figure is
(a) `3R Omega,`
(b) `((3)/(2))R Omega`
(c) `2R Omega`
(d) `((2)/(3))R Omega`

What is the equivalent resistance between A and B of network .Each resistance is of R Omega

The equivalent resistance between the point P and Q in the network given here is eqyal to (given r = (3)/(2) Omega)

What is the equivalent resistance between A and B in the figure below if R = 3 Omega

Find the equivalent resistance between the terminals A and B in the network shown figure. Given each resistor R of 10Omega .

The potential difference in volt across the resistance R_(3) in the circuit shown in figure, is (R_(1)=15Omega,R_(2)=15Omega, R_(3)=30Omega, R_(4)=35Omega)

For infinite ladder network containing identical resistance of R Omega each, are combined as shown in figure. The equivalent resistance between A and B is R_(AB) and between A and C is R_(AC) . Then the value (R_(AB))/(R_(AC)) is :

In the circuit shown in figure Current through R_(2) is zero if R_(4) = 2 Omega and R_(3) = 4 Omega In this case

(a) Given n resistors each of resistance R . How will you combine them to get the (i) maximum (ii) minimum effective resistance ? What is the ratio of the maximum to minimum resistance ? (b) Given the resistances of 1 Omega, 2 Omega, 3 Omega , how will you combine them to get an equivalent resistance of (i) (11//3)Omega (ii) (11//5)Omega (iii) 6 Omega (iv) (6//11) Omega ? (c) Determine the equivalent resistance of networks shown in Figure.

In Fig. 27-43, the current in resistance 6 is i_(6)= 2.80 A the resistances are R_(1)=R_(2)=R_(3)=2.00 Omega, R_(4)=16.0 Omega, R_(5)=8.00 Omega and R_(6)=4.00 Omega . Wat is the emf of the ideal battery?