`(1-1/2)times(1-1/3)times......times(1-1/n)=?`
`(a) 0`
`(b) 1`
`(c) 1/n`
`(d) 1/(n-1)`

Find the value of ( 1 - 1/3 ) ( 1 - 1/4 ) ( 1 - 1/5 ) ---------- ( 1 - 1/n ) is ( a ) 2/n ( b ) 4/n ( c ) 3/n ( d ) 5/n

Evaluate : (1 - 1/3 )^2 times ( 1 - 1/4 )^2 times ( 1 - 1/5 )^2 ------- ( 1 - 1/n )^2 is equal to :

9xx(-1/3)xx(-3)xx(-1/9)= 1 (b) -1 -3 (d) 3

D = ( 1/2 )^2 times ( 2/1 )^-2 times ( 1/2 )^0 times ( 2/1 )^-1 , then find D

(2^(n+3)-10times2^(n+1))/(2^(n+1)times6)=

The simplest value of (1)/(1xx2)+(1)/(2xx3)+(1)/(3xx4)+backslash+(1)/(9xx10) is (1)/(10) (b) (9)/(10) (c) 1 (d) 10

lim_(x->oo) [(1)/(1times2)+(1)/(2times3)+(1)/(3times4)+.....+(1)/(n(n+1))]

Simplify (1-1/2)xx(1-1/3)xx(1-1/4)xx(1-1/5)=......... A) 1/2 B) 1/5 C) 4/5 D) 5

Let f(x)=x/(1+x^n)^(1/n) for nge2 and g(x)=ubrace(fofo…of)_("f occurs n times")(x) . Then intx^(n-2)g(x)dx equals (A) 1/(n(n-1))(1+nx^n)^(1-1/n)+K (B) 1/(n-1)(1+nx^n)^(1-1/n)+K (C) 1/(n(n+1))(1+nx^n)^(1+1/n)+K (D) 1/(n+1)(1+nx^n)^(1-1/n)+K

Evaluate : ( 1/b + 1 ) times ( 1/c + 1 ) times ( 1/b ) times ( 1/c )