Check `2/7times(3/5times4/9)=(2/7times3/5)times4/9`

-(2)/(9)times(9)/(5)times(5)/(2)times(7)/(5)

Simplify -(2)/(3)times5(1)/(2)times2times7(5)/(6)times(9)/(11)

[(-7)times(-9)] times(3)=(-7)times [(-9)times(3)]

Proved that (2)/(3)times[(-6)/(7)times(4)/(5)]=[(2)/(3)times(4)/(5)]times((-6)/(7))

Evaluate : ( c ) 3/4 times 1/5 times 3/9 ( d ) 1/3 times 2/4 times 5/3

solve it : (ii) (-3)/(5)times(-3)/(5)times(-3)/(5)times(-3)/(5) (iii) (-9)/(2)times(4)/(2)times(-4)/(2)times(-4)/(2)times(-4)/(2)times(-4)/(2) (iv) (-5)/(3)times(-5)/(3)times(-5)/(3)times(-5)/(3) (v) (-6)/(2)times(-6)/(2)times(-6)/(2)times(-6)/(2)times(-6)/(2)

(1)/(1times3)+(1)/(3times5)+(1)/(5times7)+(1)/(7times9)+(1)/(9times11)+(1)/(11times13)

A real number (2^(2)times3^(2)times7^(2))/(2^(2)times5^(3)times3^(5)times7^(4)) will have

Evaluate : 8/5 times 5/9 times 7/(-3) times 1/4