Check whether `[((-2)/(-3))times1/5]times((-2)/7)=((-2)/(-3))times[1/5times((-2)/7)]`

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[((-2)/(-3))times(1)/(5)]times((-2)/(7))=((-2)/(-3))times[(1)/(5)times((-2)/(7))]

Show : [ ( (-2 ) /( -3 )) times 1/5 ] times ( -2/7 ) = ( (-2 ) /( -3 ) ) times [ 1/5 times ( -2/7 ) ]

Proved that (2)/(3)times[(-6)/(7)times(4)/(5)]=[(2)/(3)times(4)/(5)]times((-6)/(7))

((-4)/(3))times(1)/(2)+((-4)/(3))times((-7)/(5))

(2)/(5)times((-3)/(7))-(1)/(6)times(3)/(2)+(1)/(14)times(2)/(5)

(2)/(5)times(-(3)/(7))-(1)/(6)times(3)/(2)+(1)/(14)times(2)/(5)

Simplify (3^(-5)times5^(-7)times(-2)^(3))/(3^(4)times5^(-2)times(-2)^(-3))

[(1)/(5)times(1)/(4)],[ (1)/(5)times(7)/(2)]

5(1)/(7)times3(2)/(4)

(1/3times-1/2)times5/6 = (5/6 times 1/3)times-1/2