Fill `(-5/7)times[......times(-4/7)]=(-5/7)times2/5+.....times(-4/7)`

Similar Questions

Explore conceptually related problems

Evaluate : ( -5/ 7 ) times [ 2/5 + ( -4/7 ) ] = ( -5/7 ) times 2/5 + --- times ( -4/7 )

(5)/(7)times(5)/(7)times(5)/(7)times(5)/(7)

Proved that (2)/(3)times[(-6)/(7)times(4)/(5)]=[(2)/(3)times(4)/(5)]times((-6)/(7))

(5*10^(4))times(7times10^(7))

[((-2)/(-3))times(1)/(5)]times((-2)/(7))=((-2)/(-3))times[(1)/(5)times((-2)/(7))]

Evaluate : 5/7 times 5/7 times 5/7 times 5/7

Solve: 5/7 times 5/7 times 5/7 times 5/7

Show : ( -5/2 times -7/4 ) times 1/3 = -5/2 times ( -7/4 times 1/3 )

(3)/(4)xx(5)/(7)

Evaluate : (5/7)^3 times ( 5/7 )^(-6) times ( 1/3 )^(-2 ) times ( 3/5 )^-2