NaCl is doped with `2xx10^(-3)` mol % `SrCl_2` , the concentration of cation vacancies is

If NaCl is doped with 10^(-3) mol % SrCl_2 , what is the concentration of cation vacancies?

If NaCl is doped with 10^(-2) mol % SrCl_2 , what is the concentration of cation vacancies?

If NaCl is doped with 10^(-4)mol% of SrCl_(2) the concentration of cation vacancies will be (N_(A)=6.02xx10^(23)mol^(-1))

If NaCl is doped with 10^(-8)mol% of SrCl_(2) the concentration of cation vacancies will be (N_(A)=6.02xx10^(23)mol^(-1))

If NaCl is doped with 10^(-3) mol% of SrCl_(2) , what is the concentration of cation vacancies?

If NaCl is doped with 10^(-3) mol% of SrCl_(2) , what is the concentration of cation vacancies?

If NaCl is doped with 10^(-3) mol% of SrCl_(2) , what is the concentration of cation vacancies?

If NaCl is doped with 10^(-3) mol% of SrCl_(2) , what is the concentration of cation vacancies?

If NaCl is doped with 10^(-3) mol% GaCl_(3) , what is the concentration of the cation vacancies?

Assertion : When 1.0 mol of NaCl is doped with 10^(-3) mol SrCl_2 , the number of cationic sites remaining vacant is 10^(-3) . Reason : Each SrCl_2 unit produces tow cationic vacancy.