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The dimensions of a/b in the equation P...

The dimensions of `a/b` in the equation `P=(a-t^(2))/(bx)` where `P` is pressure, `x` is distance and `t` is time are

A

`ML^(1)T^(-1)`

B

`M^(2)LT^(-1)`

C

`ML^(0)T^(-2)`

D

`M^(0)L^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
C

`P = (a-t^(2))/(bx) = a/(bx) - t^(2)/(bx)`
By the principle of homogeneity.
`[P] =("force")/("area") =a/(b[x])`
`ML^(-1)T^(-2) = a/b [1/L] rArr a/b = MT^(-2)`
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