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A projectile is fired with velocity `v_(0)` at angle `60^(@)` with horizontal. At top os its trajectory it explodes into three fragments of equal masses. First fragment retraces the path, second moves vertically upwards with speed `(3v_(0))/(2)`. Speed of the third fragment is

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The correct Answer is:
5

Let velocity of third fragment be `vecv`
`vecP_(i) = vecP_(f)`
`rArr 3m v_(0)/2 hati = -m v_(0)/2 hati + m (3v_(0))/2 hatj + mvecv`
`vecv = 4 v_(0)/2 hati - (3v_(0))/2 hatj`
`rArr v = (5v_(0))/2`
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