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Incomes of x and y are in the ratio 4 : ...

Incomes of x and y are in the ratio 4 : 3. Their expenditures are in the ratio 12 : 7. Both save Rs 3200 at the end of the month, then the income of x is :

A

Rs 6000

B

Rs8000

C

Rs2000

D

Rs4000

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, let's break it down: 1. **Define the Variables**: - Let the incomes of X and Y be represented as \(4A\) and \(3A\) respectively, based on the given ratio of their incomes (4:3). - Let the expenditures of X and Y be represented as \(12B\) and \(7B\) respectively, based on the given ratio of their expenditures (12:7). 2. **Set Up the Savings Equation**: - According to the problem, both X and Y save Rs 3200 at the end of the month. Therefore, we can write the following equations based on the savings: - For X: \[ \text{Income of X} - \text{Expenditure of X} = \text{Savings of X} \] \[ 4A - 12B = 3200 \quad \text{(1)} \] - For Y: \[ \text{Income of Y} - \text{Expenditure of Y} = \text{Savings of Y} \] \[ 3A - 7B = 3200 \quad \text{(2)} \] 3. **Multiply the Equations**: - To eliminate \(B\), we can multiply equation (1) by 7 and equation (2) by 12: - From (1): \[ 7(4A - 12B) = 7(3200) \] \[ 28A - 84B = 22400 \quad \text{(3)} \] - From (2): \[ 12(3A - 7B) = 12(3200) \] \[ 36A - 84B = 38400 \quad \text{(4)} \] 4. **Subtract the Equations**: - Now, subtract equation (3) from equation (4): \[ (36A - 84B) - (28A - 84B) = 38400 - 22400 \] \[ 36A - 28A = 16000 \] \[ 8A = 16000 \] 5. **Solve for A**: - Divide both sides by 8: \[ A = \frac{16000}{8} = 2000 \] 6. **Calculate the Income of X**: - Now that we have the value of \(A\), we can find the income of X: \[ \text{Income of X} = 4A = 4 \times 2000 = 8000 \] Thus, the income of X is **Rs 8000**.
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