Home
Class 9
MATHS
A man gets a simple interest of Rs. 2500...

A man gets a simple interest of Rs. 2500 on a certain principal at the rate of 10% per annum in 5 years . What compound interest will the man get on twice the principal in two years at the same rate?

A

Rs. 1500

B

Rs. 2100

C

Rs. 1750

D

Rs. 1350

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will first find the principal amount using the given simple interest, and then we will calculate the compound interest on twice that principal amount. ### Step 1: Find the Principal Amount We know the formula for Simple Interest (SI): \[ SI = \frac{P \times R \times T}{100} \] Where: - \( SI \) = Simple Interest (Rs. 2500) - \( P \) = Principal amount (unknown) - \( R \) = Rate of interest (10%) - \( T \) = Time (5 years) Substituting the known values into the formula: \[ 2500 = \frac{P \times 10 \times 5}{100} \] ### Step 2: Simplify the Equation First, simplify the right side: \[ 2500 = \frac{50P}{100} \] This simplifies to: \[ 2500 = \frac{P}{2} \] ### Step 3: Solve for Principal (P) To find \( P \), multiply both sides by 2: \[ P = 2500 \times 2 = 5000 \] So, the principal amount is Rs. 5000. ### Step 4: Calculate Compound Interest on Twice the Principal Now, we need to find the compound interest on twice the principal amount, which is: \[ 2P = 2 \times 5000 = 10000 \] Using the compound interest formula: \[ CI = P \left(1 + \frac{R}{100}\right)^n - P \] Where: - \( P = 10000 \) - \( R = 10\% \) - \( n = 2 \) years ### Step 5: Substitute Values into the Compound Interest Formula Substituting the values into the formula: \[ CI = 10000 \left(1 + \frac{10}{100}\right)^2 - 10000 \] This simplifies to: \[ CI = 10000 \left(1 + 0.1\right)^2 - 10000 \] \[ CI = 10000 \left(1.1\right)^2 - 10000 \] ### Step 6: Calculate \( (1.1)^2 \) Calculating \( (1.1)^2 \): \[ (1.1)^2 = 1.21 \] ### Step 7: Substitute Back to Find CI Now substitute back into the equation: \[ CI = 10000 \times 1.21 - 10000 \] \[ CI = 12100 - 10000 \] \[ CI = 2100 \] ### Final Answer The compound interest on twice the principal in two years at the same rate is Rs. 2100. ---
Promotional Banner

Topper's Solved these Questions

  • IMO QUESTION PAPER 2018 SET A

    SCIENCE OLYMPIAD FOUNDATION |Exercise ACHIEVERS SECTION|5 Videos
  • IMO QUESTION PAPER 2018 SET A

    SCIENCE OLYMPIAD FOUNDATION |Exercise ACHIEVERS SECTION|5 Videos
  • IMO QUESTION PAPER 2017 SET B

    SCIENCE OLYMPIAD FOUNDATION |Exercise ACHIEVERS SECTION|5 Videos
  • IMO QUESTION PAPER 2018 SET B

    SCIENCE OLYMPIAD FOUNDATION |Exercise Achievers Section |5 Videos

Similar Questions

Explore conceptually related problems

A man gets a simple interest of Rs 1000 on a certain principal at the rate of 5 p.c.p.a. in 4 years. What compound interest will the man get on twice the principal in 2 years at the same rate? (a) Rs 1000 (b) Rs 1005 (c) Rs 10125 (d) 11025 (e) None of these

What is the simple interest (in Rs) on a principal of Rs 1800 at the rate of 8% per annum for 3 years?

Simple interest on a principal of Rs. 100 for 2 years at the rate of 5% per annum is ____.

A principal gets increased by 21% in 2 years at compound interest. What will be the simple interest on Rs. 1000 for 4 years at the same rate of interest ?

The simple interest accrued on a sum of certain principal in 8 yr at the rate of 13% per year is ₹6500. What would be the compound interest accrued on that principal at the rate of 8% per year in 2yr?