Home
Class 7
MATHS
Amrita and her grandmother both had birt...

Amrita and her grandmother both had birthdays on same day. The sum of their ages is 100 years. Amrita's grandmother's age is 4 times her age. Find their present ages.

A

25 years, 75 years

B

20 years, 80 years

C

22 years, 88 years

D

25 years, 100 years

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the present ages of Amrita and her grandmother given that their combined age is 100 years and that Amrita's grandmother is 4 times Amrita's age. ### Step-by-Step Solution: 1. **Define Variables**: - Let Amrita's age be \( A \). - Then, her grandmother's age will be \( 4A \) (since her grandmother's age is 4 times Amrita's age). 2. **Set Up the Equation**: - According to the problem, the sum of their ages is 100 years. Therefore, we can write the equation: \[ A + 4A = 100 \] 3. **Combine Like Terms**: - Combine the terms on the left side of the equation: \[ 5A = 100 \] 4. **Solve for Amrita's Age**: - To find \( A \), divide both sides of the equation by 5: \[ A = \frac{100}{5} = 20 \] 5. **Find Grandmother's Age**: - Now that we have Amrita's age, we can find her grandmother's age: \[ \text{Grandmother's age} = 4A = 4 \times 20 = 80 \] 6. **Conclusion**: - Amrita's present age is 20 years, and her grandmother's present age is 80 years. ### Final Answer: - Amrita's age: 20 years - Grandmother's age: 80 years
Promotional Banner

Topper's Solved these Questions

  • IMO MODEL TEST PAPER 2

    SCIENCE OLYMPIAD FOUNDATION |Exercise Achievers Section |5 Videos
  • IMO MODEL TEST PAPER 2

    SCIENCE OLYMPIAD FOUNDATION |Exercise Achievers Section |5 Videos
  • IMO MODEL TEST PAPER - 1

    SCIENCE OLYMPIAD FOUNDATION |Exercise Achievers Section|5 Videos
  • IMO QOESTION PAPER 2017-18 SET-B

    SCIENCE OLYMPIAD FOUNDATION |Exercise EVERYDAY MATHEMATICS |10 Videos

Similar Questions

Explore conceptually related problems

The product of Tanvy's age (in years) 5 years ago and her age 8 years later is 30. Find her present age.

A girl is 28 years younger than her father. The sum of their ages is 50 years. Find the ages of the girl and her father.

The sum of the ages of father and his son is 45 years.5 years ago the products of their ages was 124. Find the present ages.

Sum of ages of mother and her daughter is 60 years. After 15 years mother's age will be twice as that of her daughter's age at that time. Find their present ages.

The present age of a woman is 3 years more than three times the age of her daughter. Three years hence, the woman's age will be 10 years, more than twice the age of her daughter. Find their present ages.

After 15 years,Rani's age will become 4 xx that of her present age.Find her presentage?

Sum of the present ages of Manish and Savita is 31. Manish's age 3 years ago was 4 times the age of Savita. Find their present ages.

Reena is 6 years older than her brother Ajay. If the sum of their ages is 28 years, what are their present ages ?

The sum of the reciprocals of Meena's ages (in years) 3 years ago and 5 year hence is (1)/(3). Find her present age.