(1) `int_0^pi sin x dx=2`

int_0^(pi) sin3x dx=2/3

You are examine these two statements carefully and select and answer Assertion (A) : int_0^pi sin^7 x dx =2 int_0^(pi//2) sin^7 xdx Reason ( R): sin^7x is an odd function

int_0^(pi/2) sin x dx

int_(0)^(pi) [2sin x]dx=

int_0^(pi//2) sin^3 x dx

(i) int_0^(pi/2) sin^2 x dx (ii) int_0^(pi//2) cos^2 x dx

int_0^(pi/2) sin^6x dx

int_(0)^(pi)x sin^(2)x dx=