`Cos^6A + Sin^6A = 1-3Sin^2ACos^2A`

sin^(6)A + cos^(6)A + 3sin^(2)A.cos^(2)A=

sin ^ (6) A + cos ^ (6) A = 1-3sin ^ (2) A cos ^ (2) A

Prove the following identities: sin^(6)A+cos^(6)A=1-3sin^(2)A cos^(2)A

sin^6A+cos^6A+3sin^2A.cos^2A=

cos ^ (6) A + sin ^ (6) A = 1-k sin ^ (2) (2A) rArr k =

Prove that : sin^(6)A+cos^(6)A+3sin^(2)Acos^(2)A=1

cos ^ (6) A + sin ^ (6) A = (1) / (4) (1 + 3cos ^ (2) 2A) cos6A + sin A = (1 + 3cos22A)

Prove that cos^4A+sin^4A+2sin^2Acos^2A=1

(sin A sin2A + sin3A sin6A) / (sin A cos2A + sin3A cos6A) = tan5A

sin ^(6) a + cos ^(6) A - 1 is equal to A. -3 sin ^(2) A cos ^(2) A B. 1 - 3 sin A cos A C. 1 + 3 sin ^(2) A cos ^(2) A D. 0