Recommended Questions
- cos20^(@)*cos40^(@)*cos60^(@)*cos80^(@)=(1)/(16)
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- Prove that: cos20^0cos40^0cos60^0cos80^0=1/(16)
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- Prove that cos20^0cos40^0cos60^0cos80^0=1/(16)dot
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- cos20 ^ (@) cos40 ^ (@) cos60 ^ (@) cos80 ^ (@) - (1) / (16) =
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- cos 20^@.cos 40^@.cos 60^@ cos 80^@=
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- Find : cos 20^0cos 40^0cos 60^0cos 80^0
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- Prove that: i) cos10^(@)cos30^(@)cos50^(@)cos70^(@)=3/16 ii) cos20...
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- cos20^(@).cos40^(@).cos60^(@).cos80^(@)=1/16
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- cos20^(@).cos40^(@).cos60^(@).cos80^(@)=1/16
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