Fill `2/(-3)+1/9=1/9+(-2)/(.....)=(......)/9`

1:(4)/(9):(2)/(3)=

Fill in the blanks. (i) (25)/(8) divide (.......) = -10 . (ii) (-8)/(9) xx (.........) =(-2)/(3) . (iii) (-1)+(.........) =(-2)/(9) . (iv) (2)/(3)- (.........) =(1)/(15) .

16/9 xx (-1(1)/2)^(3)=

Prove that (9(1)/(3).9^((1)/(9)).9^((1)/(77)).........oo)=3

(9^(2))/(3)=(?)/(9)

(1)/(9)+(2)/(9)+(3)/(9)=

[{(-1/3)^2}^(-2)]^(-1) = (a) 1/(81) (b) 1/9 (c) -1/(81) (d) -1/9

Fill in the blanks: (9)/(8)+(...)=(-3)/(2)

(1) / (3) x ^ (2) -2x-9