`∫1/(x^2 + 4x + 5) dx`

∫(3x^2 + 4x + 5) dx

int ( x +2)/( 2x ^(2) + 6x + 5) dx = p int ( 4x +6)/( 2x ^(2) + 6x +5) dx + (1)/(2) int (1)/( 2x ^(2) + 6x + 5) dx then p

Evaluate : int ( ( 5x + 1 )/( x^2 + 4 ) ) dx

int(1)/(4x^(2)-4x+5)dx

int_1^2(x^3+4x+5)dx

Evaluate: (i) int1/(4x^2+12 x+5)\ dx (ii) int1/(x^2-10 x+34)\ dx

int(x)/(x^(2)+4x+5)dx

intsqrt(x^2-4x-5)dx=

int(2x^2-1)/((x^2+4)(x^2+5))dx=

int(2x^2-1)/((x^2+4)(x^2-5))dx=