If kinetic energy of an electron is given by (13.6`+-`1)eV. Then calculate the uncertainty in position of electron.(`m_e`=`10^(-30)`kg)

If the uncertainty in velocity of electron is 1*10^7 ms^-1 then the uncertainty in position of electron will be (mass of an electron is 9 *10^-28 g)

The kinetic energy of an electron is 4.55×10 ^ (−25) J. Calculate the wavelength, (h= 6.6×10 ^ (−34) Jsec,mass of electron= 9.1×10^ (−31) kg).

The uncertainty in the momentum of a particle is 6xx10^(-9)kg ms^(-1) . Calculate the uncertainty in its position.

What is the uncertainty in velocity of an electron if the uncertainty in its position is 10^(-10) m ? Mass of the electron is 9.1 xx 10^(-31) kg and h = 6.6 xx 10^(-34) m^(2) s^(-1) ?

What is the uncertainty in velocity of an electron if the uncertainty in its position is 10^(-10) m ? Mass of the electron is 9.1 xx 10^(-31) kg and h = 6.6 xx 10^(-34) m^(2) s^(-1) ?

The uncertainty in the momentum of an electron is 1.0 xx 10^(-5) kgms^(-1) . The uncertainty in its position will be : ( h = 6.626 xx 10^(-34) Js )

energy of an electron system in the first excited state is -13.6 eV . This is

The uncertainty in the momentum of a particle is 6.0 xx 10^(-2) kg m s^(-1) .Calculate the uncertainty in the position

The uncertainty in momentum of an electron is 1 xx 10^-5 kg - m//s . The uncertainty in its position will be (h = 6.62 xx 10^-34 kg = m^2//s) .

The uncertainty in momentum of an electron is 1 xx 10^-5 kg - m//s . The uncertainty in its position will be (h = 6.62 xx 10^-34 kg = m^2//s) .