The tetrahedral voids present in `0.2` mol of a compound forming hexagonal close packing crystal structure are `X times10^(23)`.The `x` is (Given `N_(A)=6times10^(23)` )

Total no. of voids in 0.5 mole of a compound forming hexagonal closed packed structure are :

A compound forms hexagonal close packed structure. What is the total number of voids in 0.5 mol of it.

The number of octahedral and tetradedral holes respectively present in a hexagonal close packed(hep) crystal of 'X' atoms are

Two elements A and B have atomic masses 40 and 60 respectively. If B from hcp arrangements and A is occupying 1/3 of thte tetrahedral voids, then what will be number of hexagonal primitive unit cells w.r.t. B atoms in 130mg of the substance? (Given : N_(A) = 6 xx 10^(23)

Ga (atomic mass 70 u) crystallizes in a hexagonal dose packed structure. The total number of voids in 0.581 g of Ga is __ xx10^(23) . (Round off to the Nearest Integer). [Given : N_(A)=6.023 xx 10^(23)]