`((1+cos theta)/(sin theta))^2=(1+cos theta)/(1-cos theta)`

(sin theta)/(1+cos theta) is equal to (1+cos theta)/(sin theta)(b)(1-cos theta)/(cos theta)(c)(1-cos theta)/(sin theta) (d) (1-sin theta)/(cos theta)

1- (sin ^ (2) theta) / (1 + cos theta) + (1 + cos theta) / (sin theta) - (sin theta) / (1-cos theta) - (1) / (sec theta)

1-(sin^(2)theta)/(1+cos theta)+(1+cos theta)/(sin theta)-(sin theta)/(1-cos theta) equals

(sin theta)/(1-cos theta)=(1+cos theta)/(sin theta)

Prove that: ((1)/(cos theta)-(1)/(sin theta))(1+(sin theta)/(cos theta)+(cos theta)/(sin theta))=sec theta tan theta-cosec theta cot theta

Prove: ((1+sin theta-cos theta)/(1+sin theta+cos theta))^(2)=(1-cos theta)/(1+cos theta)

(1 + cos theta + sin theta) / (1 + cos theta-sin theta) = (1 + sin theta) / (cos theta)

(1+cos theta+sin theta)/(1+cos theta-sin theta)=(1+sin theta)/(cos theta)

cos theta/(1+sin theta)=(1-sin theta)/cos theta