`sqrt12-:sqrt4`

The expression sqrt(12+6sqrt(3))+sqrt(12-6sqrt(3)) simplifies to

sqrt(21-4sqrt5+8sqrt3-4sqrt12)=

The value of sin^(-1){cot(sin^(-1)(sqrt((2-sqrt3)/4)+cos^(-1)(sqrt(12)/4)+sec^(-1)sqrt2)} is

Which is greater sqrt(11)-sqrt(6) or sqrt(17)-sqrt(12) ?

Find the value of '(sqrt(32)+sqrt(48))/sqrt(8)+sqrt(12))

The value of sqrt(2-1)/sqrt(2)+3-2sqrt(2)/(4)+(5sqrt2-7/6)sqrt(2)+17-12sqrt(2)/(16)+..+++..+ add.infty is

sin^(-1)sqrt((2-sqrt(3))/4)+cos^(-1)(sqrt(12)/4)+sec^(-1)(sqrt(2))= (a) 0 (b) pi/4 (c) pi/6 (d) pi/2

10sqrt(12) -: 2sqrt(3)

{:("Column A"," ","Column B"),(sqrt(12.5)+sqrt(12.5),,sqrt(25)):}

Which of the following is greater? sqrt(13)-sqrt(12),sqrt(14)-sqrt(13)