`|[sin^2theta,-cos^2theta],[tan^2theta,sin^2theta]|=?`

tan^2theta-sin^2theta=tan^2theta.sin^2theta

prove that- sin^2theta/cos^2theta+cos^2theta/sin^2theta=1/ (sin^2thetacos^2theta)-2

tan^(2)theta-tan^(2)(90^(@)-theta)=(sin^(2)theta-cos^(2)theta)/(sin^(2)theta cos^(2)theta)

If sin theta=cos theta , then 2tan^(2)theta+sin^(2)theta-1= _____

If f(theta)=|[cos^(2)theta,cos theta sin theta,-sin theta],[cos theta sin theta,sin^(2)theta,cos theta],[sin theta,-cos theta,0]| , then f((pi)/(12))

Prove: (sec theta+cos theta)(sec theta-cos theta)=tan^(2)theta+sin^(2)theta

If cos theta+cos^(2)theta=1 then sin^(2)theta+2sin^(2)theta+sin^(2)theta=

If tan theta=(3)/(4), then (4sin^(2)theta-2cos^(2)theta)/(4sin^(2)theta+3cos^(2)theta)

If tan theta=(3)/(4), then (4sin^(2)theta-2cos^(2)theta)/(4sin^(2)theta+3cos^(2)theta)

If f (theta) = [[cos^(2) theta , cos theta sin theta,-sin theta],[cos theta sin theta , sin^(2) theta , cos theta ],[sin theta ,-cos theta , 0]] "then " f (pi/7) is