`(sin^2theta-cos^2theta)/(cos^2theta-sin^2theta)=?`

sin^2theta+cos^4theta=cos^2theta+sin^4theta

If tan theta=(12)/(13), evaluate (2sin theta cos theta)/(cos^(2)theta-sin^(2)theta)

int(2sin2 theta-cos theta)/(6-cos^(2)theta-4sin theta)d theta

If tan theta=(12)/(13) then value of (2sin theta cos theta)/(cos^(2)theta-sin^(2)theta) is

The value of (2(sin2 theta+2cos^(2)theta-1))/(cos theta-sin theta-cos3 theta+sin3 theta)=

If |{:(1+cos^(2)theta,sin^(2)theta,4cos6theta),(cos^(2)theta,1+sin^(2)theta,4cos6theta),(cos^(2)theta,sin^(2)theta,1+4cos6theta):}|=0 , and theta in (0,(pi)/(2)) , then value of theta is

find value of |A|=|[sin^(2)theta,-cos^(2)theta],[cos^(2)theta,-sin^(2)theta]|

(sin3 theta+cos3 theta)/(cos theta-sin theta)=1+2xx sin2 theta

(1+sin 2theta+cos 2theta)/(1+sin2 theta-cos 2 theta) =