`sin A cos (A-B) - cos A sin (A-B)` =

For all values of angle A and B(i)sin(A-B)=sin A cos B-cos A sin B(ii)sin(A+B)=sin A cos B+cos A sin B

If A=30o and B=60o ,verify that sin(A+B)=sin A cos B+cos A sin B(ii)cos(A+B)=cos A cos B-sin A sin B

If = 60^(@) and B=30^(@) , then show that : sin A cos B+ cos A sin B= sin (A+B)

Prove that: i) sin(A+B)cos(A-B)-cos(A+B)sin(A-B)=sin2B ii) cos(45^(@)-A)cos(45^(@)-B)-sin(45^(@)-A)sin(45^(@)-B)=sin(A+B)

If A=B=60o, verify that cos(A-B)=cos A cos B+sin A sin B(iii)sin(A-B)=sin A cos B-cos A sin B(iii)tan(A-B)=(tan A-tan B)/(1+tan A tan B)

sin 2A + sin 2B + sin 2 (A-B)= A) 4 sin A * sin B * sin (A-B) B) 4 sin A * cos B * cos (A-B) C) 4 cos A * sin B * cos (A-B) D) 4 cos A * cos B * sin (A-B)

Prove by vector method that sin(A-B)=sin A cos B-cos A sin B and sin(A+B)=sin A cos B+cos A sin B

If sin A=a cos B and cos A=b sin B then tan^(2)B =

If A and B are complementary angles, then the value of sin A cos B + cos A sin B - tanA tan B + sec^(2) A - cot^2 B is

If sin A=a cos B and cos A=b sin B then (a^(2)-1)tan^(2)A+(1-b^(2))tan^(2)B is equal to