`(1+Cosθ)/Sin^2θ = 1/(1-Cosθ)`

Solve, integrate ∫ (dθ)/(sin^2θ * cos^2θ)

Prove the following trigonometric identities: sinθ/(1+cosθ) + (1+cosθ)/sinθ = 2/sinθ

If (sinθ/(1+ cosθ)) + ((1 +cosθ)/sinθ) = 4/sqrt3 0^circ lt θ lt 90^circ , then the value of (tanθ + secθ)^(-1) is : यदि (sinθ/(1+ cosθ)) + ((1 +cosθ)/sinθ) = 4/sqrt3 0^circ lt θ lt 90^circ ,, तो (tanθ + secθ)^(-1) का मान है :

If 5sin θ – 4cos θ = 0, 0^circ lt θ lt 90^circ , then the value of (5sinθ− 2cosθ)/ (5 sin θ + 3cosθ) is: यदि 5sin θ – 4cos θ = 0, 0^circ lt θ lt 90^circ है, तो (5sinθ− 2cosθ)/ (5 sin θ + 3cosθ) का मान है:

x = a(θ - sinθ), y = a(1 + cosθ) Find dy/dx

(1) / (1 + sin A) + (1) / (1-sin A) = 2sec ^ (2) A

(1-sin A-cos A) ^ (2) = 2 (1-sin A) (1-cos A)

If cos^(2) θ - sin^(2) θ - 3cosθ +2 =0 , 0^circ lt θ lt 90^circ , then what is the value of 4cosecθ + cotθ ? यदि cos^(2) θ - sin^(2) θ - 3cosθ +2 =0 , 0^circ lt θ lt 90^circ , है तो 4cosecθ + cotθ का मान कितना है?

If θ lies in the first quadrant and cos^(2) θ – sin^(2) θ = 1/2 , then the value of tan^(2)2θ + sin^(2)3θ is: यदि θ प्रथम चतुथथांश में है और cos^(2) θ – sin^(2) θ = 1/2 , तो tan^(2)2θ + sin^(2)3θ का मान है:

If 2cos^(2)θ + 3sinθ = 3 , where 0^circ lt θ lt 90^circ , then what is the value of sin^(2)2θ + cos^2 (θ) + tan^(2)2θ + cos^(2) 2θ = ? यदि 2cos^(2)θ + 3sinθ = 3 , जहा 0^circ lt θ lt 90^circ तो sin^(2)2θ + cos^(2(θ + tan^(2)2θ + cos^(2)2θ का मान बराबर है :