A point object starts from rest at t=0s with constant acceleration. itf it covers a distance S between t=2s to t=4s , then distance covered br object between t=6s to t=8s will be equal to

A car starts from rest and moves with constant acceleration. In first t seconds it covers distance x. Then distance covered by it in next t seconds will be:-

A particle starts from the rest, moves with constant acceleration for 15s. If it covers s_1 distance in first 5s then distance s_2 in next 10s, then find the relation between s_1 & s_2 .

An object accelerates from rest to a velocity 27.5ms in 10s ,then find distance covered by the object during next "10s

A particle moves according to the law x = acos (pi) / (2) The distance covered by it in the time interval between t=0 to t=3s is

In a certain circuit current changes with time according to i=2sqrt(t) RMS value of current between t=2s to t=4s will be

A point mass starts moving in straight line with constant acceleration a from rest at t=0 . At time t=2s , the acceleration changes the sign remaining the same in magnitude. The mass returns to the initial position at time t=t_(0) after start of motion. Here t_(0) is

A particle starts from rest and accelerated as shown in the graph. Determine (a). The particle's speed at t=10s and at t=20 s (b). The distance travelled in the first 20s .

Starting from rest, the acceleration of a particle is a=2(t-1). The velocity of the particle at t=5s is :-