`(x^2-1)dy/dx+2xy`=1

Solve (x^2+1)dy/dx+2xy=sqrt(x^2+4)

The equation of curve passing through origin and satisfying the differential equation (1 + x^2)dy/dx + 2xy = 4x^2 , is

IF of the following differential equations. (1-x ^2)(dy //dx) + 2xy = x ( 1- x^2 ) ^(1//2)

Find the particular solution of the differential equation (1+x^(2))(dy)/(dx)+2xy=(1)/(1+x^(2)) given that at x=1 , y=0 .

(1-x^(2))(dy)/(dx)-2xy=x-x^(3)

Solve: (1+x^2)(dy)/(dx)+2xy=cosx

The solution of x^(2)(dy)/(dx)-xy=1+cosy/x is

Solve the differential equation (x-1)(dy)/(dx)=2xy , given that y(2)=1

The solution of (1-x^2) dy/dx+2xy-xsqrt(1-x^2)=0 , is (A) y/((1-x^2))=1/sqrt(1-x^2)+C (B) y(1-x^2)=sqrt(1-x^2)+C (C) y(1-x^2)^(3/2)=sqrt(1-x^2)+C (D) none of these

Find the general solution of the differential equation (x-1)(dy)/(dx) + xy = (x+1)^(2)