`int (logx)/(1+logx)^2 dx`

Write a value of int(1+logx)/(3+xlogx)\ dx

Evalaute: int((logx-1)/(1+(logx)^2))^2dx

If int[(logx-1)/(1+(logx)^2)]^2dx=f(x)/(1+(g(x))^2)+c , then (A) f(x)=x (B) f(x)=x^2 (C) g(x)=logx (D) g(x)=(logx)^2

Evaluate int((log x-1)/(1+(logx)^(2)))^(2)dx

Evaluate: int(logx)/(x^2)\ dx

Evaluate: int{1/(logx)-1/((logx)^2)}\ dx

Evaluate: int{1/(logx)-1/((logx)^2)}\ dx

Evaluate: int1/(xlogx(2+logx) dx

Evaluate: int(log(logx)+1/((logx)^2))dx

Evaluate: int(log(logx)+1/((logx)^2))dx