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If p+frac{1}{p}=2,then the value of p^2+...

If `p+frac{1}{p}=2`,then the value of `p^2+frac{1}{p^2}`is

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Prove. If cosalpha +isinalpha is the solution of the equatioin x^n +p_1x^(n-1) +p_2 x^(n-2) +…+p_n =0 where p_1,p_2,p_3,…p_n are real then the value of p_1 sinalpha+p_2 sin2alpha+p_3sin3alpha+…+p_nsin nalpha=0